Limma experiment design and making contrasts
0
0
Entering edit mode
Kesava • 0
@8c9ea7d2
Last seen 12 months ago
United States

Hi,

I am a novice working on a 450k methylation array analysis. I have a very simple design which is to see the differentially methylated genes b/w smoking (1) vs non-smoking (0). This is the following I did.

# using smoking_primary as the factor in interest
design <- model.matrix(~0 + smoking_primary)

# Make contrasts 0 is the control and 1 is the test
contrast <- makeContrasts(smoking_primary0 - smoking_primary1, 
                          levels = design)

# fit to methyaltion set
fit <- lmFit(m_norm_qc, design)
fit2 <- contrasts.fit(fit, contrast)
fit2 <- eBayes(fit2)

## Add the annotations to the results
ann450kSub <- ann450k[match(rownames(m_norm_qc),ann450k$Name),
                     c(1:4,12:19,24:ncol(ann450k))]

DMPs <- topTable(fit2, num=Inf, coef=1, genelist = ann450kSub)

Could you please review this and tell me if it is the correct way to do the analysis?

In addition, how should I approach adding covariates to my design? If you could point me to the resource where I could get more info that would be very helpful.

Thank you for your time on this post.

limma methylationArrayAnalysis • 947 views
ADD COMMENT
0
Entering edit mode
ADD REPLY
0
Entering edit mode

Thank you, wasn't sure how this works. Now I know.

ADD REPLY

Login before adding your answer.

Traffic: 813 users visited in the last hour
Help About
FAQ
Access RSS
API
Stats

Use of this site constitutes acceptance of our User Agreement and Privacy Policy.

Powered by the version 2.3.6