Question

Limma gives big p-values for large LFC

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chipolino • 0

@chipolino-15565

Last seen 5.1 years ago

Hi,

I am doing RNA-seq with 2 groups: treatment and control. For both of them, I have 2 replicates. I use limma-voom for this. But I am quite confused by the results I see in the toptable output. For example, I have these genes in my original table of raw counts (where Jc is the treatment, and N is the control):

enter image description here

And here is the same matrix after voom normalization.

enter image description here

And this is the output of toptable for the same genes

enter image description here

As you can see adjusted p-value is quite large... Some of them would not pass the 0.1 FDR threshold. I would expect them to be way smaller with such changes in expression. What am I missing here? What is wrong?

Thank you.

limma voom • 1.5k views

ADD COMMENT • link updated 5.1 years ago by Gordon Smyth 51k • written 5.1 years ago by chipolino • 0

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You don't show any code, so who knows?

ADD REPLY • link 5.1 years ago Aaron Lun ★ 28k

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here is the code sample I use:

designMatrix <- model.matrix(~0 + Analysis, md)

contrastMatrix <- makeContrasts(
A1 = Analysis1 - Analysis2,
levels = colnames(designMatrix)) #Analysis is a factor column: 1 - treatment; 2 - control

v <- voom(expr_mat, designMatrix, plot=FALSE) #expr_mat is similar to the one above

vfit <- lmFit(v, designMatrix)

vfit <- contrasts.fit(vfit, contrasts=contrastMatrix)

efit <- eBayes(vfit)

DEgenes <- topTable(efit, number = Inf) #and I have large p-values

ADD REPLY • link 5.1 years ago chipolino • 0

score 2 · Answer 1 · 2019-10-25

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Gordon Smyth 51k

@gordon-smyth

Last seen 24 minutes ago

WEHI, Melbourne, Australia

If your data is noisy, it will be hard to be significant results from such small samples sizes. Remember that significance depends on variability as well as on the fold-changes and variability is computed from all the genes, not just the four genes you show.

In any case, limma is giving much smaller p-values than a t-test would give for the same data. For example, here are the t-test results for the EOMES logCPM values:

> x <- c(8.102, 7.92)
> y <- c(-5.71, -4.57)
> t.test(x,y)

        Welch Two Sample t-test

data:  x and y
t = 22.783, df = 1.0509, p-value = 0.02407
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
  6.605754 19.696246
sample estimates:
mean of x mean of y 
    8.011    -5.140

ADD COMMENT • link 5.1 years ago Gordon Smyth 51k

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Thank you for your answer! I have a related question, suppose that in my expression matrix I have 3 conditions: treatment A, treatment B and control (2 replicates everywhere). Now my goal is to compare treatment A to control. My question is, should I do voom and further analysis on the whole expr matrix (with the appropriate contrast matrix) or should I first take a subset of expr matrix with the columns only for treatment A and control (and then do voom and other steps)? Will there be any difference?

ADD REPLY • link 5.1 years ago chipolino • 0