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pingzhao Hu
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@pingzhao-hu-685
Last seen 10.2 years ago
Hi,
I have an Affymetrix dataset. There are 24 arrays.
There are three factors: time, sex (M and F) and strain (NOD,R and
D4).
Sex has two levels and strain has 3 levels. I am only interested in
interaction between sex and strain. So the formula will like:
~time+sex*strain.
The question I want to ask is
" Does the effect of strain change between male and female?"
For example I want to select genes:
(1) differentially expressed genes between male and female only at NOD
not
R and D4?
(2) differentially expressed genes between male and female only at R
not
NOD and D4?
(3) differentially expressed genes between male and female only at D4
not
NOD and R?
I construct design and contrast matrix as follow.
> design
maleNOD maleR maleD4 femaleNOD femaleR femaleD4
[1,] 1 0 0 0 0 0
[2,] 1 0 0 0 0 0
[3,] 0 1 0 0 0 0
[4,] 0 1 0 0 0 0
[5,] 0 0 1 0 0 0
[6,] 0 0 1 0 0 0
[7,] 0 0 0 1 0 0
[8,] 0 0 0 1 0 0
[9,] 0 0 0 0 1 0
[10,] 0 0 0 0 1 0
[11,] 0 0 0 0 0 1
[12,] 0 0 0 0 0 1
[13,] 1 0 0 0 0 0
[14,] 1 0 0 0 0 0
[15,] 0 1 0 0 0 0
[16,] 0 1 0 0 0 0
[17,] 0 0 1 0 0 0
[18,] 0 0 1 0 0 0
[19,] 0 0 0 1 0 0
[20,] 0 0 0 1 0 0
[21,] 0 0 0 0 1 0
[22,] 0 0 0 0 1 0
[23,] 0 0 0 0 0 1
[24,] 0 0 0 0 0 1
> contrast
maleNOD-femaleNOD maleR-femaleR maleD4-femaleD4
maleNOD 1 0 0
maleR 0 1 0
maleD4 0 0 1
femaleNOD -1 0 0
femaleR 0 -1 0
femaleD4 0 0 -1
Are these correct????
-----------------------------------------------------------
in lmFit there are three methods to fit linear models (gls,ls and
robust).
Since affy. data has no duplicate spots for each gene on the same
array, Is
it still
suitable to use gls method???. The example in user manual at 7.2
used gls (default).
The big question is that the results based on gls and robust methods
are
very different:
For example, the number of differentially expressed genes based on
these two
mthods are aso follows (p-value<=0.01):
maleNOD-femaleNOD maleR-femaleR maleD4-femaleD4
gls 7 7 14
robust 14 229 500
How can I decide which method (gls or robust) to use?
Thanks
pingzhao