User: Kavitha Venkatesan

Reputation:
30
Status:
New User
Location:
United States
Last seen:
2 years, 7 months ago
Joined:
8 years, 7 months ago
Email:
k*****************@gmail.com

Posts by Kavitha Venkatesan

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Job: Bioinformatics Scientist opportunity in Novartis Oncology, Cambridge, MA
... Hi List, We have an exciting opportunity for a talented Bioinformatics Scientist in the Oncology Department at Novartis Institutes for Biomedical Research (NIBR). We are a science-driven group impacting cancer drug discovery and development starting from early target discovery through to early/mid ...
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Comment: C: evaluating a character string as a variable name in an ExpressionSet object
... > > > Thanks for all your suggestions. Both Martin's suggestions below (simpler > > solution) and Saroj's approach worked. > > FYI- Saroj's approach which when adapted to my situation would entail the > > following code: > >>for(i in varLabels(sample.ExpressionSet ...
written 8.6 years ago by Kavitha Venkatesan30
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Answer: A: evaluating a character string as a variable name in an ExpressionSet object
... Thanks for all your suggestions. Both Martin's suggestions below (simpler solution) and Saroj's approach worked. FYI- Saroj's approach which when adapted to my situation would entail the following code: >for(i in varLabels(sample.ExpressionSet)) > print( eval(parse(text=paste("sample.Expressi ...
written 8.6 years ago by Kavitha Venkatesan30
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evaluating a character string as a variable name in an ExpressionSet object
... I would like to know how to evaluate a character string as a variable name in R. Specifically, I need to "compute" the variable name in the phenoData slot of an ExpressionSet object. > varLabels(sample.ExpressionSet) [1] "sex" "type" "score" Now I need to retrieve the factors sample.Expressi ...
written 8.6 years ago by Kavitha Venkatesan30 • updated 8.6 years ago by Saroj Mohapatra450

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