User: Kavitha Venkatesan
Kavitha Venkatesan • 30
- Reputation:
- 30
- Status:
- New User
- Location:
- United States
- Last seen:
- 3 years, 8 months ago
- Joined:
- 9 years, 7 months ago
- Email:
- k*****************@gmail.com
Posts by Kavitha Venkatesan
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... Hi List,
We have an exciting opportunity for a talented Bioinformatics Scientist in the Oncology Department at Novartis Institutes for Biomedical Research (NIBR). We are a science-driven group impacting cancer drug discovery and development starting from early target discovery through to early/mid ...
written 3.7 years ago by
Kavitha Venkatesan • 30
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... >
> > Thanks for all your suggestions. Both Martin's suggestions below
(simpler
> > solution) and Saroj's approach worked.
> > FYI- Saroj's approach which when adapted to my situation would
entail the
> > following code:
> >>for(i in varLabels(sample.ExpressionSet ...
written 9.7 years ago by
Kavitha Venkatesan • 30
0
votes
2
answers
585
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... Thanks for all your suggestions. Both Martin's suggestions below
(simpler
solution) and Saroj's approach worked.
FYI- Saroj's approach which when adapted to my situation would entail
the
following code:
>for(i in varLabels(sample.ExpressionSet))
> print( eval(parse(text=paste("sample.Expressi ...
written 9.7 years ago by
Kavitha Venkatesan • 30
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... I would like to know how to evaluate a character string as a variable
name
in R. Specifically, I need to "compute" the variable name in the
phenoData
slot of an ExpressionSet object.
> varLabels(sample.ExpressionSet)
[1] "sex" "type" "score"
Now I need to retrieve the factors sample.Expressi ...
written 9.7 years ago by
Kavitha Venkatesan • 30
• updated 9.7 years ago by
Saroj Mohapatra • 450
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