LRT results DESeq2
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bekah ▴ 40
@bekah-12633
Last seen 5.7 years ago

Hi,

​I am running analysis on RNA Seq data using DESeq2, I have two "treatments" for each sample each with two levels

status: sham or infected
temperature: high or low.

​I have run the LRT to look at whether I am make sure I have not made any assumptions based on experimental design on whether genes are significantly dif expressed. To do this I have used the LRT

dstemp_lrt<-DESeq(dstemp, test="LRT", reduced= ~status)
res_LRT<-results(dstemp_lrt)

to give:
log2 fold change (MLE): temperature L vs H
LRT p-value: '~ status + temperature' vs '~ status'

​Am I correct in thinking that this gives the Pvalues of the genes significantly differentially expressed as a result of whether it was sham or infected in comparison to those genes sig. differentially expressed when temperature is also factored in (the interaction)?
Therefore I should also run with "reduced=~temperature" to test the same but with just temperature and then compare the two lists?


Best wishes,

​Rebekah

 

deseq2 Job • 1.3k views
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Ah cheers! So this can be used to identify if the DEG I have found when looking at the four individual experimental groups (infected L, infected H, control L, control H) can be attributed to the difference in temperature or difference in status?

 

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Basically, yes. You should see which have the differences.

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@mikelove
Last seen 1 hour ago
United States

The p-value you have there tests for differences in gene expression due to temperature, accounting for differences due to status.

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