I have a list having granges as follows:

    $
    File1.bed
    
    
    GRanges object with 3 ranges and 2 metadata columns:
    
          seqnames    ranges strand |        name
    
             <Rle> <IRanges>  <Rle> | <character>
    
      [1]    chr1   [ 4,  6]      + |         TF1
    
      [2]     chr1  [ 9,  9]      + |         TF1
    
      [3]     chr1  [11, 12]      - |         TF1
    
      -------
    
      seqinfo: 2 sequences from an unspecified genome; no seqlengths
    
    $
    File1.bed
    
    
    GRanges object with 3 ranges and 2 metadata columns:
    
          seqnames    ranges strand |        name     score
    
             <Rle> <IRanges>  <Rle> | <character> <numeric>
    
      [1]    chr2   [ 5, 60]      + |         TF4         0
    
      [2]     chr1  [21, 90]      + |         TF4         0
    
      [3]     chr2  [23, 30]      - |         TF4         0
    
      -------
    
      seqinfo: 3 sequences from an unspecified genome; no seqlengths

I would like to make these lists one list, to concatenate them into one.
I am using 

    data_bed = unlist(as(data_bed, "GRangesList"))

But it is giving me an error since the grange objects have different columns and so cannot be concatenated into one. Is there a way to subselect the columns I need inorder to create a list from the columns I want?

Any thoughts?

Input data:

structure(list(`C:/Users/Documents/test_data/File1.bed` = <S4 object of class structure("GRanges", package = "GenomicRanges")>, 
    `C:/Users/Documents/test_data/File2.bed` = <S4 object of class structure("GRanges", package = "GenomicRanges")>), .Names = c("C:/Users/Documents/test_data/File1.bed", 
"C:/Users/Documents/test_data/File2.bed"))

On a single GRanges, you could do something like x[,"name"]. Just do that over the whole list.