Conversion of LogFC to FC
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nia ▴ 30
@nia-12707
Last seen 19 months ago

Hi everyone, I have write a script to analyze microarray illumina data by using Limma package. The script generated a table and it consist a logFC column. Now, I wish to know the FC values but here I have a confusion that should I go with 2^logFC or 10^logFC. I am looking for help.

limma logfc fc • 2.9k views
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@gordon-smyth
Last seen 1 hour ago
WEHI, Melbourne, Australia

Just type ?topTable to see that logFC is log2 rather than log10.

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Thankyou for the quick response, that means I have to go with 2^logFC.

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Yes.

Alternatively, you can use sign(logFC)*2^abs(logFC) which has some symmetrical properties.

For a logFC of -3, instead of getting 2^-3 = 1/8 = 0.125, you get -8.

Here you have to interpret -x as 1/x. This could help. Of course, there is no in ]-1:1[.

> 2^3
[1] 8
> 2^(-3)
[1] 0.125
> sign(-3)*2^abs(-3)
[1] -8
> sign(3)*2^abs(3)
[1] 8
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Very detailed information thank you. The point I learn is if I do 2^logFC then I have to interpret that -logfc as 1/-logfc.

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No I understand what you mean. Here is what I mean:

If logFC = 3, then FC = 2^3 = 8

If logFC = -3, then FC = 2^-3 = 1/8 that can also be noted -8 using the convention that -x means 1/x

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I can't help but feel that this notation causes more problems than it solves; having the magnitude of the fold-change and the sign of the log-fold change is begging to be mistaken for one or the other. Certainly, if I saw a negative "fold change" in an analysis report, I would assume that the author made a typo and actually meant "log-fold change".

If one finds log-values or fold-changes below 1 too difficult to comprehend, a more mathematically appropriate notation would be to state 1/x rather than -x, where x = 2^abs(logFC) for logFC < 0. Then you get the magnitude of the fold change without repurposing the minus symbol to represent something other than its intended meaning.

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