Robert Castelo <robert.castelo at="" ...=""> writes: <snip> > the newline character '\n' i was giving to the separator 'sep' parameter > in the paste function should be written as '\\\n'. doing it this way my > former example works: > > library(GOstats) > library(Rgraphviz) > > goterms <- eapply(GOTERM,Term) > g <- GOGraph("GO:0016265",GOBPPARENTS) > g <- removeNode("all",g) > mt <- match(nodes(g),names(goterms)) > nodattr <- makeNodeAttrs(g,label=paste(nodes(g),goterms[mt],sep="\\\n"), > shape="ellipse",fillcolor="#f2f2f2", > fixedsize=FALSE) > plot(g,nodeAttrs=nodattr) > > ... and no, writing '\\n' doesn't work. > <snip> Thankyouthankyouthankyouthankyouthankyou! Spent about 4 hours trying to get multi-line labels, trying from one to four backslashes. Finally I searched the help archive and found your solution. In my case, I wanted to split up long lines, so I was using gsub(): tmpGraphAttrs$nodeAttrs$label <- gsub("([[:print:]]{10})[[:space:]]", "\\1\\\\\n", tmpGraphAttrs$nodeAttrs$label) In that case, I had to use _five_ backslashes to get what I was after! (Escape the first backslash, escape the second backslash, then \n.) --which results in something like this: tmpGraphAttrs$nodeAttrs$label[1] GO:0009605 "response to\\\nexternal stimulus" So the node label string itself must have a triple-backslashed 'n' for a functional newline, which requires even more backslashing in (g)sub. I had been trying to get either '\n' or '\\n' in the string, but hadn't realized that I need '\\\n' for it to work. Thanks again! -Brian Peyser news at at@bpeyser.dot.fastmail.dot.net (use your biological supercomputer to fix that before replying)