about model.matrix and helmert
0
0
Entering edit mode
@gregory-voisin-945
Last seen 9.9 years ago
Canada
Hello, I use model.matrix () to create my contrast to do a canonical analysis with rdatest() and I would like your opinion on my problem. DATA: I work with a microarray experiment composed 12 chips, 2 factors ( mutation , treatement) , each has 2 levels (absence , presence) , 3 biological replicat. DESIGN: no-mut1 no-mut2 no-mut3 mut1 mut2 mut3 TREATED_no-mut1 TREATED_no-mut2 TREATED_no-mut3 TREATED_mut1 TREATED_mut2 TREATED_mut3 CODE IN R: facteur_mutation = gl(2,3, length = 12) facteur_oxidant = gl(2,6) helmert = model.matrix (~facteur_mutation*facteur_oxidant, contrast = list(facteur_mutation ="contr.helmert", facteur_oxidant= "contr.helmert")) MY RESULT ISSUE FROM CANONICAL ANALYSIS: 63 % of variance explained by mutation 17% of variance explained by Treatement. QUESTION: Given that 20 % of variance is no explained , how to integrage ( in R code ) the factor " replication " I have tried to add in my original code this part : the line factor_replication = c(1,2,3,1,2,3,1,2,3,1,2,3) helmert = model.matrix (~facteur_mutation*facteur_oxidant* facteur_replication , contrast = list(facteur_mutation ="contr.helmert", facteur_oxidant= "contr.helmert", facteur_replication= "contr.helmert")) but I don't think that it's OK, because ( if I have good comprehension of what is helmert is ), the scalar product is no 0 ) . Moreover , the result "said"  that the variance explained by replication is 2 %... It's very low , too low... What Does you think about integrate replication factor in my model.matrix ? Thanks Greg Centre de recherche du CHUM. Montreal [[alternative HTML version deleted]]
Microarray Microarray • 809 views
ADD COMMENT

Login before adding your answer.

Traffic: 798 users visited in the last hour
Help About
FAQ
Access RSS
API
Stats

Use of this site constitutes acceptance of our User Agreement and Privacy Policy.

Powered by the version 2.3.6