Use DESeq2 to test if hybrid > max(parent1, parent2) | hybrid < min(parent1, parent2)
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Entering edit mode
@will-landau-6891
Last seen 9.5 years ago
United States

I'm trying to use DESeq2 to test if hybrid > max(parent1, parent2) | hybrid < min(parent1, parent2), where parent1, parent2, and hybrid are three genetic varieties. The DESeq2 framework doesn't directly do this kind of hypothesis test, so I test a bunch of contrasts and then pick the p-value for the appropriate one for each gene. I don't really need an exact p-value, I just need some way to rank the genes. 

The problem is that all the adjusted p-values returned by DESeq are 1 and I don't know why. I include a minimal working example below.


library(DESeq2)

 

# Toy setting with 1000 genes, 3 groups, and 4 replicates per group.

 

genes = 1000

groups = 3

replicates = 4

 

# Generate the count table. This is a terrible simulation in 

# general, but all I'm trying to do is check my usage of DESeq2.

 

lambda = rgamma(genes*groups*replicates, 200, 5)

counts = matrix(rpois(genes*groups*replicates, lambda), nrow = genes, ncol = groups*replicates)

 

# The colData objecct has the experimental design. The three groups (genetic varieties)

# are parent1, parent2, and hybrid. My goal is to find out if hybrid > max(parent1, parent2)

# or hybrid < min(parent1, parent2) in terms of gene expression. 

 

colData = DataFrame(row.names=LETTERS[1:(3*replicates)],

  Treatment = factor(rep(c("parent1", "parent2", "hybrid"), each = replicates))

)

 

# Fit the DESeq model.

 

se = SummarizedExperiment(assays = SimpleList(counts = counts), colData = colData)

dds <- DESeqDataSet(se = se, design = ~ Treatment - 1)

dds <- DESeq(dds, betaPrior = F)

 

# For each gene, I extract the DESeq adjusted p-values for the four hypothesis 

# tests below and then choose one based on the DESeq2 model coefficients. 

 

# p-values for testing if parent1 > hybrid

p1.g.h = results(dds, lfcThreshold = dim(counts)[1], altHypothesis = "greater", 

  contrast = c(Treatmenthybrid = -1, Treatmentparent1 = 1, Treatmentparent2 = 0))$padj

 

# p-values for testing if hybrid > parent2

h.g.p2 = results(dds, lfcThreshold = dim(counts)[1], altHypothesis = "less", 

  contrast = c(Treatmenthybrid = -1, Treatmentparent1 = 0, Treatmentparent2 = 1))$padj

 

# p-values for testing if parent2 > hybrid

p2.g.h = results(dds, lfcThreshold = dim(counts)[1], altHypothesis = "greater", 

  contrast = c(Treatmenthybrid = -1, Treatmentparent1 = 0, Treatmentparent2 = 1))$padj

 

# p-values for testing if hybrid > parent1

h.g.p1 = results(dds, lfcThreshold = dim(counts)[1], altHypothesis = "less", 

  contrast = c(Treatmenthybrid = -1, Treatmentparent1 = 1, Treatmentparent2 = 0))$padj

 

# DESeq2 model coefficients. 

 

cf = coef(dds)

p1 = cf[, "Treatmentparent1"]

p2 = cf[, "Treatmentparent2"]

h = cf[, "Treatmenthybrid"]

 

# For each gene, I use the coefficients below to pick which p-value to use.

 

df = cbind(p1, p2, h, p1.g.h, p2.g.h, h.g.p1, h.g.p2)

 

my_pvals = apply(df, 1, function(x){

  if((min(x["p1"], x["p2"]) <= x["h"]) && (x["h"] <= max(x["p1"], x["p2"])))

    return(0)

  else if(x["h"] > x["p1"] && (x["p1"] >= x["p2"]))

    return(x["h.g.p1"])

  else if(x["h"] > x["p2"] && (x["p2"] >= x["p1"]))

    return(x["h.g.p2"])

  else if(x["h"] < x["p1"] && (x["p1"] <= x["p2"]))

    return(x["p1.g.h"])

  else if(x["h"] < x["p2"] && (x["p2"] <= x["p1"]))

    return(x["p2.g.h"])

  else

    return(1)

})

 

# All p-values are either 0 or 1. Why is that?

 

table(my_pvals)

 

# And all the adjusted p-values are 1

table(p1.g.h)

table(p2.g.h)

table(h.g.p1)

table(h.g.p2)

 

 

 

deseq2 DESeq2 • 1.3k views
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2
Entering edit mode
@mikelove
Last seen 5 days ago
United States

I started to parse your code, but stopped at:

lfcThreshold = dim(counts)[1]

Why are you setting a threshold on log fold changes equal to the number of rows of the count matrix?

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0
Entering edit mode

I have no idea how that argument got there, I didn't mean to set lfcThreshold at all. Removing it seems to remove or mask the problem in that example. Thank you!

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