Hey everyone,

I have a bit more of a general R question which I cant really figure out. I have a matrix of the type

   [A] [B] [C]
[1] 3   5   2
[2] 1   3   6
[3] 1   6   2

and a vector in the form

   [A] [B] [C]
[1] 2   4   7

What I am trying to get out is in this case 3 new columns attached to the initial matrix which would lets say go through all rows in column A and compare it to the value for [A] in the vector. If its higher than I would like to have a 1 in the new column, if lower a 0. And then for B and so on. In this example:

   [A] [B] [C] [A.2][B.2][C.2]
[1] 3   5   2    1    1    0 
[2] 1   3   6    0    0    0 
[3] 1   6   2    0    1    0

Anyone knows a good way to do this? I think I am getting too confused with multiple loops.

Thank you so much,

Ben

This isn't the place to ask that question, you should probably try stack overflow for this sort of thing. However, it's early and I fancied a go...

foo           <- matrix(sample(1:20, 9),3,3)
baa           <- c(8,5,12)
out           <- baa < t(foo)
out[out == F] <- 0
out[out == T] <- 1