asking for some code
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zhihua li ▴ 120
@zhihua-li-1129
Last seen 9.6 years ago
Dear netters, Now I have a matrix at hand. For each row, I want to find the Q5(the 5th quantile) and the Q95, and put them in a function fyn(), which will return two numbers n and m(n<m). then="" i'll="" take="" each="" element="" (say="" x)="" in="" the="" row="" one="" by="" one,="" and="" perform="" a="" judgment:="" if="" x<n,="" do="" sub1(x);="" if="" n<="x&lt;=m," do="" sub2(x);="" if="" x="">m, do sub3(x). The process goes on through each row in the matrix. This program isnot very complicated, but hard enough for me...........So could anybody give me a prototype of the code? Thanks a lot!
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@sean-davis-490
Last seen 3 months ago
United States
Taking this apart: to find the Q5(quantile): See ?quantile for each row: See ?apply if x<n {="" do="" stuff="" }="" else="" if="" ((x="">n) & (x<m)) {="" do="" other="" stuff="" }="" else="" {="" do="" other="" other="" stuff="" }="" sean="" on="" mar="" 9,="" 2005,="" at="" 4:15="" am,="" zhihua="" li="" wrote:=""> Dear netters, > > Now I have a matrix at hand. For each row, I want to find the Q5(the > 5th quantile) and the Q95, and put them in a function fyn(), which > will return two numbers n and m(n<m). then="" i'll="" take="" each="" element="" (say=""> x) in the row one by one, and perform a judgment: if x<n, do="" sub1(x);=""> if n<=x<=m, do sub2(x); if x>m, do sub3(x). The process goes on > through each row in the matrix. This program isnot very complicated, > but hard enough for me...........So could anybody give me a prototype > of the code? > Thanks a lot! > > _______________________________________________ > Bioconductor mailing list > Bioconductor@stat.math.ethz.ch > https://stat.ethz.ch/mailman/listinfo/bioconductor
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A slightly more intuitive way is to cut() the variable returning labels, which you can then feed into switch(). # simulate data set.seed(1) x <- runif(5) x [1] 0.2655087 0.3721239 0.5728534 0.9082078 0.2016819 Let us say that n=0.25 and m=0.6. my.switch.fn <- function(x ){ y <- cut( x, breaks=c(0, 0.25, 0.6, 1), labels=FALSE ) z <- switch(y, "1" = x, "2" = x + 1, "3" = x + 2 ) return(z) } sapply( x, my.switch.fn ) [1] 1.2655087 1.3721239 1.5728534 2.9082078 0.2016819 In the case of 2 breakpoints, my example does not look much shorter than the if-else clause below. The drawback of my suggestion is that you need to know the min and max occuring values values (in this case 0 and 1) and switch does not have a default value. Regards, Adai On Wed, 2005-03-09 at 05:56 -0500, Sean Davis wrote: > Taking this apart: > > to find the Q5(quantile): > See ?quantile > > for each row: > See ?apply > > if x<n {=""> do stuff > } else if ((x>n) & (x<m)) {=""> do other stuff > } else { > do other other stuff > } > > Sean > > On Mar 9, 2005, at 4:15 AM, zhihua li wrote: > > > Dear netters, > > > > Now I have a matrix at hand. For each row, I want to find the Q5(the > > 5th quantile) and the Q95, and put them in a function fyn(), which > > will return two numbers n and m(n<m). then="" i'll="" take="" each="" element="" (say=""> > x) in the row one by one, and perform a judgment: if x<n, do="" sub1(x);=""> > if n<=x<=m, do sub2(x); if x>m, do sub3(x). The process goes on > > through each row in the matrix. This program isnot very complicated, > > but hard enough for me...........So could anybody give me a prototype > > of the code? > > Thanks a lot! > > > > _______________________________________________ > > Bioconductor mailing list > > Bioconductor@stat.math.ethz.ch > > https://stat.ethz.ch/mailman/listinfo/bioconductor > > _______________________________________________ > Bioconductor mailing list > Bioconductor@stat.math.ethz.ch > https://stat.ethz.ch/mailman/listinfo/bioconductor >
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On Wed, Mar 09, 2005 at 02:41:36PM +0000, Adaikalavan Ramasamy wrote: > sapply( x, my.switch.fn ) > [1] 1.2655087 1.3721239 1.5728534 2.9082078 0.2016819 > > > In the case of 2 breakpoints, my example does not look much shorter than > the if-else clause below. The drawback of my suggestion is that you need > to know the min and max occuring values values (in this case 0 and 1) > and switch does not have a default value. You can use Inf/-Inf to get around not knowing he min and max, and you can indeed give a further argument to switch such like switch(x, 1 = "One", 2 = "Two", "Everything else") Kasper
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On Wed, Mar 09, 2005 at 06:06:26PM +0100, Kasper Daniel Hansen wrote: > On Wed, Mar 09, 2005 at 02:41:36PM +0000, Adaikalavan Ramasamy wrote: > > sapply( x, my.switch.fn ) > > [1] 1.2655087 1.3721239 1.5728534 2.9082078 0.2016819 > > > > > > In the case of 2 breakpoints, my example does not look much shorter than > > the if-else clause below. The drawback of my suggestion is that you need > > to know the min and max occuring values values (in this case 0 and 1) > > and switch does not have a default value. > > You can use Inf/-Inf to get around not knowing he min and max, and you > can indeed give a further argument to switch such like > switch(x, 1 = "One", > 2 = "Two", > "Everything else") > Sorry, I was a bit quick: that stuff only works when x is a character variable.
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Thanks Kasper. I did not know R's switch now has a default value which is very convenient for many things I am doing. And the use of -Inf and Inf is excellent suggestion as well. I would like to add that the values of 1, 2, ... have to be characters as well. Otherwise you have syntax error. For example : x <- 5 switch(as.character(x), "1" = "one", "2" = "two", "Everything else") Regards, Adai On Wed, 2005-03-09 at 18:06 +0100, Kasper Daniel Hansen wrote: > On Wed, Mar 09, 2005 at 02:41:36PM +0000, Adaikalavan Ramasamy wrote: > > sapply( x, my.switch.fn ) > > [1] 1.2655087 1.3721239 1.5728534 2.9082078 0.2016819 > > > > > > In the case of 2 breakpoints, my example does not look much shorter than > > the if-else clause below. The drawback of my suggestion is that you need > > to know the min and max occuring values values (in this case 0 and 1) > > and switch does not have a default value. > > You can use Inf/-Inf to get around not knowing he min and max, and you > can indeed give a further argument to switch such like > switch(x, 1 = "One", > 2 = "Two", > "Everything else") > > Kasper >
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Thanks for all the help! I'm on the border of resolving the problem but......... for the if-else clause, I alwayse got error message when using if..else if....else.....statement. I looked it up in the R mannual and found that R only have a "if....else..." structure, but doesn't have something like "if....elseif....elseif......else....."? Does it mean that only two conditions can be selected in the conditional execution grammer of R? for the cut() and switch() clause, I found it's very efficient in application to a vector. but when I wanna use it in a matrix row by row, it's less convenient (or I didn't write the smart code). >From: Adaikalavan Ramasamy <ramasamy@cancer.org.uk> >Reply-To: ramasamy@cancer.org.uk >To: Sean Davis <sdavis2@mail.nih.gov> >CC: zhihua li <lzhtom@hotmail.com>, BioConductor mailing list <bioconductor@stat.math.ethz.ch> >Subject: Re: [BioC] asking for some code >Date: Wed, 09 Mar 2005 14:41:36 +0000 > >A slightly more intuitive way is to cut() the variable returning labels, >which you can then feed into switch(). > ># simulate data > set.seed(1) > x <- runif(5) > x >[1] 0.2655087 0.3721239 0.5728534 0.9082078 0.2016819 > > >Let us say that n=0.25 and m=0.6. > >my.switch.fn <- function(x ){ > > y <- cut( x, breaks=c(0, 0.25, 0.6, 1), labels=FALSE ) > > z <- switch(y, > "1" = x, > "2" = x + 1, > "3" = x + 2 > ) > return(z) >} > >sapply( x, my.switch.fn ) >[1] 1.2655087 1.3721239 1.5728534 2.9082078 0.2016819 > > >In the case of 2 breakpoints, my example does not look much shorter than >the if-else clause below. The drawback of my suggestion is that you need >to know the min and max occuring values values (in this case 0 and 1) >and switch does not have a default value. > >Regards, Adai > > >On Wed, 2005-03-09 at 05:56 -0500, Sean Davis wrote: > > Taking this apart: > > > > to find the Q5(quantile): > > See ?quantile > > > > for each row: > > See ?apply > > > > if x<n {=""> > do stuff > > } else if ((x>n) & (x<m)) {=""> > do other stuff > > } else { > > do other other stuff > > } > > > > Sean > > > > On Mar 9, 2005, at 4:15 AM, zhihua li wrote: > > > > > Dear netters, > > > > > > Now I have a matrix at hand. For each row, I want to find the Q5(the > > > 5th quantile) and the Q95, and put them in a function fyn(), which > > > will return two numbers n and m(n<m). then="" i'll="" take="" each="" element="" (say=""> > > x) in the row one by one, and perform a judgment: if x<n, do="" sub1(x);=""> > > if n<=x<=m, do sub2(x); if x>m, do sub3(x). The process goes on > > > through each row in the matrix. This program isnot very complicated, > > > but hard enough for me...........So could anybody give me a prototype > > > of the code? > > > Thanks a lot! > > > > > > _______________________________________________ > > > Bioconductor mailing list > > > Bioconductor@stat.math.ethz.ch > > > https://stat.ethz.ch/mailman/listinfo/bioconductor > > > > _______________________________________________ > > Bioconductor mailing list > > Bioconductor@stat.math.ethz.ch > > https://stat.ethz.ch/mailman/listinfo/bioconductor > > >
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zhihua li ▴ 120
@zhihua-li-1129
Last seen 9.6 years ago
Ya, it works! maybe I made some mistakes writing the if...else clause yesterday. Thanks! >From: "STKH (Steen Krogsgaard)" <stkh@novozymes.com> >To: "zhihua li" <lzhtom@hotmail.com> >Subject: RE: [BioC] asking for some code >Date: Thu, 10 Mar 2005 14:20:28 +0100 > >Is there anything wrong with > >if (clause1) { >... >} else if (clause2) { >... >} else if (clause3) { >... >} else { >... >} > >That's what you do in Pascal! > >/Steen > >-----Original Message----- >From: bioconductor-bounces@stat.math.ethz.ch >[mailto:bioconductor-bounces@stat.math.ethz.ch] On Behalf Of zhihua li >Sent: 10. marts 2005 14:12 >To: ramasamy@cancer.org.uk >Cc: bioconductor@stat.math.ethz.ch >Subject: Re: [BioC] asking for some code > > >Thanks for all the help! I'm on the border of resolving the problem >but......... > >for the if-else clause, I alwayse got error message when using if..else >if....else.....statement. I looked it up in the R mannual and found that >R only have a "if....else..." structure, but doesn't have something like > >"if....elseif....elseif......else....."? Does it mean that only two >conditions can be selected in the conditional execution grammer of R? > >for the cut() and switch() clause, I found it's very efficient in >application to a vector. >but when I wanna use it in a matrix row by row, it's less convenient (or >I >didn't write the >smart code). > > > > >From: Adaikalavan Ramasamy <ramasamy@cancer.org.uk> > >Reply-To: ramasamy@cancer.org.uk > >To: Sean Davis <sdavis2@mail.nih.gov> > >CC: zhihua li <lzhtom@hotmail.com>, BioConductor mailing list ><bioconductor@stat.math.ethz.ch> > >Subject: Re: [BioC] asking for some code > >Date: Wed, 09 Mar 2005 14:41:36 +0000 > > > >A slightly more intuitive way is to cut() the variable returning > >labels, which you can then feed into switch(). > > > ># simulate data > > set.seed(1) > > x <- runif(5) > > x > >[1] 0.2655087 0.3721239 0.5728534 0.9082078 0.2016819 > > > > > >Let us say that n=0.25 and m=0.6. > > > >my.switch.fn <- function(x ){ > > > > y <- cut( x, breaks=c(0, 0.25, 0.6, 1), labels=FALSE ) > > > > z <- switch(y, > > "1" = x, > > "2" = x + 1, > > "3" = x + 2 > > ) > > return(z) > >} > > > >sapply( x, my.switch.fn ) > >[1] 1.2655087 1.3721239 1.5728534 2.9082078 0.2016819 > > > > > >In the case of 2 breakpoints, my example does not look much shorter > >than the if-else clause below. The drawback of my suggestion is that > >you need to know the min and max occuring values values (in this case 0 > > >and 1) and switch does not have a default value. > > > >Regards, Adai > > > > > >On Wed, 2005-03-09 at 05:56 -0500, Sean Davis wrote: > > > Taking this apart: > > > > > > to find the Q5(quantile): > > > See ?quantile > > > > > > for each row: > > > See ?apply > > > > > > if x<n {=""> > > do stuff > > > } else if ((x>n) & (x<m)) {=""> > > do other stuff > > > } else { > > > do other other stuff > > > } > > > > > > Sean > > > > > > On Mar 9, 2005, at 4:15 AM, zhihua li wrote: > > > > > > > Dear netters, > > > > > > > > Now I have a matrix at hand. For each row, I want to find the > > > > Q5(the 5th quantile) and the Q95, and put them in a function > > > > fyn(), which will return two numbers n and m(n<m). then="" i'll="" take=""> > > > each element >(say > > > > x) in the row one by one, and perform a judgment: if x<n, do=""> > > > sub1(x); if n<=x<=m, do sub2(x); if x>m, do sub3(x). The process > > > > goes on through each row in the matrix. This program isnot very > > > > complicated, but hard enough for me...........So could anybody > > > > give me a prototype of the code? Thanks a lot! > > > > > > > > _______________________________________________ > > > > Bioconductor mailing list > > > > Bioconductor@stat.math.ethz.ch > > > > https://stat.ethz.ch/mailman/listinfo/bioconductor > > > > > > _______________________________________________ > > > Bioconductor mailing list > > > Bioconductor@stat.math.ethz.ch > > > https://stat.ethz.ch/mailman/listinfo/bioconductor > > > > > > >_______________________________________________ >Bioconductor mailing list >Bioconductor@stat.math.ethz.ch >https://stat.ethz.ch/mailman/listinfo/bioconductor
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