Question

DESeq2 design for paired samples

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annamariabugaj ▴ 10

@e7994b78

Last seen 20 months ago

Norway

Hi,

I have two groups of mice - wild type and mutant in which every mice had one brain hemisphere treated/damaged (ipsi) and one hemisphere healthy (contra). I would like to assess if there is a difference in response to the treatment between WT and MUT. Another question is if the healthy hemispheres differ significantly in gene expression levels (mut vs. wt).

        > head(metaData)
    ID genotype   hemi
1 WT_1       WT Contra
2 WT_2       WT Contra
3 WT_3       WT Contra
4 WT_1       WT   Ipsi
5 WT_2       WT   Ipsi
6 WT_3       WT   Ipsi

Based on another topic (DESEq2 Paired samples Before and after treatment ) I made my design as:

~ mouseID + hemi* genotype

But I got an error message:

Error in checkFullRank(modelMatrix) : the model matrix is not full rank, so the model cannot be fit as specified. One or more variables or interaction terms in the design formula are linear combinations of the others and must be removed.Please read the vignette section 'Model matrix not full rank': vignette('DESeq2')

I read a vignette but I am still not sure how to change the design so it reflects my question (how the genotype affects the response to treatment). Or is there something I am doing wrong with the IDs, should I add a column of "mice.n" similar as in the the topic I am referring to? In that topic I understand the additional column is required because of unequal number of patients in naive/second groups.

DESeq2 paired • 1.3k views

ADD COMMENT • link updated 3.2 years ago by Michael Love 42k • written 3.2 years ago by annamariabugaj ▴ 10

score 0 · Answer 1 · 2021-08-31

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ATpoint ★ 4.5k

@atpoint-13662

Last seen 16 hours ago

Germany

Mouse ID is nested with genotype, I would omit ID from the design.

ADD COMMENT • link 3.2 years ago ATpoint ★ 4.5k

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Thank you! Is the one below correct?

~ genotype+hemi+genotype:hemi

ADD REPLY • link 3.2 years ago annamariabugaj ▴ 10

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When you read the vignette, did you read the section about individuals nested within groups? If you want to compare within mouse, that section is relevant.

ADD REPLY • link 3.2 years ago Michael Love 42k

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Hi Michael,

Thank you for pointing this out. I did not find this particular section reading the vignette before, now I understand that the additional column is the nested and it explains a lot. Thank you very much, I am not sure if I grasp the idea correctly but I will try and in case of troubles I will ask more precise questions.

ADD REPLY • link 3.2 years ago annamariabugaj ▴ 10

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edit: yes, it works perfectly, thank you so much!

 design<- (~ genotype + ind.n + genotype:ind.n + genotype:hemi)
> dds <- DESeqDataSetFromMatrix(countData = countData, 
+                               colData = metaData, 
+                               design = design, tidy = TRUE)


# Calling results
> res <- results(dds)
> mcols(res, use.names=TRUE)
DataFrame with 6 rows and 2 columns
                       type                                  description
                <character>                                  <character>
baseMean       intermediate    mean of normalized counts for all samples
log2FoldChange      results log2 fold change (MLE): genotypeMUT.hemiIpsi
lfcSE               results         standard error: genotypeMUT.hemiIpsi
stat                results         Wald statistic: genotypeMUT.hemiIpsi
pvalue              results      Wald test p-value: genotypeMUT.hemiIpsi
padj                results                         BH adjusted p-values
> # Print the coefficients
> resultsNames(dds)
[1] "Intercept"            "genotype_MUT_vs_WT"   "ind.n_2_vs_1"        
[4] "ind.n_3_vs_1"         "genotypeMUT.ind.n2"   "genotypeMUT.ind.n3"  
[7] "genotypeWT.hemiIpsi"  "genotypeMUT.hemiIpsi"
> results(dds, contrast=list("genotypeMUT.hemiIpsi","genotypeWT.hemiIpsi"))
log2 fold change (MLE): genotypeMUT.hemiIpsi vs genotypeWT.hemiIpsi 
Wald test p-value: genotypeMUT.hemiIpsi vs genotypeWT.hemiIpsi 
DataFrame with 18057 rows and 6 columns
               baseMean log2FoldChange     lfcSE      stat    pvalue      padj
              <numeric>      <numeric> <numeric> <numeric> <numeric> <numeric>

So now I can use the coefficients to make contrasts - do I understand correctly that the contrast from the vignette example (results(dds, contrast=list("grpY.cndB","grpX.cndB")) and in my case results(dds, contrast=list("genotypeMUT.hemiIpsi","genotypeWT.hemiIpsi")))

is similar to Interaction term in the design with Interaction (ignoring the individuals)? I mean if I run this design:

~ genotype+hemi+genotype:hemi

which woudl give me the coefficients:

> resultsNames(dds)
[1] "Intercept"            "genotype_MUT_vs_WT"   "hemi_Ipsi_vs_Contra" 
[4] "genotypeMUT.hemiIpsi"

should I get similar result for results(dds, name="genotypeMUT.hemiIpsi") ? Is this correct?

ADD REPLY • link 3.2 years ago annamariabugaj ▴ 10

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For confirming that a particular statistical design is what you are intending, I'd recommend working with a statistician. Beyond what we've laid out in the vignette, I don't have sufficient time to follow up on the support site with statistical design questions.

ADD REPLY • link 3.2 years ago Michael Love 42k