GenomicRanges: Take union of GRanges and keep metadata?
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endrebak85 ▴ 40
@endrebak85-10660
Last seen 5.3 years ago
github.com/endrebak/

Let us say I have two GenomicRanges objects that look like this:

library(GenomicRanges)

 gr1 <- GRanges("chr1", IRanges(c(1, 11, 21), c(9, 19, 29), names=paste0("rsid:", letters[1:3])), score=c(6,7,8))

gr2 <- GRanges("chr1", IRanges(c(1,11,31), c(9,19,39), names=paste0("dnase:", letters[1:3])), score=c(0,1,5))

I want to take the union of bins, keeping the metadata, so that I end up with:

GRanges object with 4 ranges and 2 metadata columns:
          seqnames    ranges strand |     score  score
             <Rle> <IRanges>  <Rle> | <numeric>  <numeric>
  dnase:a     chr1  [ 1,  9]      * |         0  6
  dnase:b     chr1  [11, 19]      * |         1  7
  rsid:c     chr1  [21, 29]      * |          0  8
  dnase:c     chr1  [31, 39]      * |         5  0

Ps. the final names of the sequences do not matter, ideally they should have none.

Ps2. I have more than two GenomicRanges, so great if you can solve this by calling reduce.

Edit: Currently I am here:

u = union(gr1, gr2)

values(u)$gr1 = values(gr1)

But this leads to

Error in `[[<-`(`*tmp*`, name, value = <S4 object of class "DataFrame">) :
  3 elements in value to replace 4 elements

With the method I am attempting to use  I need some way to only set values on a subset of u.

This does not work for some reason: 

elementMetadata(u[start(u) == start(gr1)])$gr1 = elementMetadata(gr1)[,1]

If you do 

elementMetadata(u)$gr1 = 0

it works

However, when I try this for gr2 it does not work:

elementMetadata(u)$gr2 = 0
 elementMetadata(u[start(u) == start(gr2)])$gr2 = elementMetadata(gr2)[,1]

The result is 

GRanges object with 4 ranges and 2 metadata columns:
      seqnames    ranges strand |       gr1       gr2
         <Rle> <IRanges>  <Rle> | <numeric> <numeric>
  [1]     chr1  [ 1,  9]      * |         6         0
  [2]     chr1  [11, 19]      * |         7         0
  [3]     chr1  [21, 29]      * |         8         0
  [4]     chr1  [31, 39]      * |         0         0
GRange genomicranges • 5.8k views
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S4Vectors Version:            0.8.11

GenomicRanges Version:            1.22.4

(both from bioconda)

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@martin-morgan-1513
Last seen 5 months ago
United States

I'm not sure that union() is doing what you think it is? It treats each range as a set of integers, and provides a compact way of representing the union of the set.

> union(GRanges("A:1-5"), GRanges("A:3-7"))
GRanges object with 1 range and 0 metadata columns:
      seqnames    ranges strand
         <Rle> <IRanges>  <Rle>
  [1]        A    [1, 7]      *
  -------
  seqinfo: 1 sequence from an unspecified genome; no seqlengths

So generally the mapping will be many-to-one. I'd guess that you were instead aiming for

u = unique(c(granges(gr1), granges(gr2)))

And then your approach but with match would seem to be good enough

mcols(u)[match(gr1, u), "gr1"] = gr1$score
mcols(u)[match(gr2, u), "gr2"] = gr2$score
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Your solution is great. The only thing that is a bit hard is to set the NA values to zero afterwards.

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endrebak85 ▴ 40
@endrebak85-10660
Last seen 5.3 years ago
github.com/endrebak/

Classier solutions welcome, but this works:

elementMetadata(u[overlapsAny(u, gr1)])$gr1 = elementMetadata(gr1)[,1]

elementMetadata(u[overlapsAny(u, gr2)])$gr2 = elementMetadata(gr2)[,1]

GRanges object with 4 ranges and 2 metadata columns:
      seqnames    ranges strand |       gr1       gr2
         <Rle> <IRanges>  <Rle> | <numeric> <numeric>
  [1]     chr1  [ 1,  9]      * |         6         0
  [2]     chr1  [11, 19]      * |         7         1
  [3]     chr1  [21, 29]      * |         8         0
  [4]     chr1  [31, 39]      * |         0         5
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