How to extract out wanted IntegerList more elegantly from nested list?
1
0
Entering edit mode
@jian_liangli-11294
Last seen 4.8 years ago

Hi :

I have list of position index in the IntegerList, and I intended to filter them given threshold, and it works well. However, I want to extract out one of specific filtered set for each IntegerList for further usage. I aware that myList is nested list , and data are very much simulated based on real data set. Is there any way to retrieve wanted IntegerList easily and elegantly? How can I make it this extraction happen? 

 

mini example :

myList <- list(f1=IntegerList(1,2,3,4,1,1,1,integer(0),1,2,4),
               f2=IntegerList(1,5,integer(0),integer(0),2,3,4,6,1,5,6),
               f3=IntegerList(1,4,6,7,2,3,3,7,2,5,7))

len <- Reduce('+', lapply(myList, lengths))
keepMe <- len >= length(myList)

I did following filtering: 

res.filt <- lapply(myList, function(elm) {
  ans <- list(keep=elm[keepMe], droped=elm[!keepMe])
  ans
})

my rough attempt output :

wantedKeep.list <- list(f1.kp=res.filt$f1$keep, f2.kp=res.filt$f2$keep, f3.kp=res.filt$f3$keep)
wantedDrop.list <- list(f1.dp=res.filt$f1$droped, f2.dp=res.filt$f2$droped, f3.dp=res.filt$f3$droped)

Based on my rough output, How can I get more elegant output ? any efficient way to achieve my output ? Can anyone point me how to do? Or any suggestion how to get my expected output ?  Thanks in advance

r s4vectors integerlist iranges • 713 views
ADD COMMENT
3
Entering edit mode
@michael-lawrence-3846
Last seen 8 weeks ago
United States

It looks like you are thnking of the data as a matrix. You can create a list matrix like this:

v <- unlist(lapply(myList, as.list), recursive=FALSE)
m <- matrix(v, length(myList), byrow=TRUE)
rownames(m) <- names(myList)

Then you can compute lengths and make the selection:

lens <- lengths(m)
dim(lens) <- dim(m)
keep <- colSums(lens) >= nrow(m)
keepList <- m[,keep,drop=FALSE]
dropList <- m[,!keep,drop=FALSE]

I will work on making some of these operations easier. But it's pretty straight-forward as is.

Is it the case that all of the elements are of length either 1 or 0? If so, it might be easier to convert the zero-length elements to NAs and drop to a vector.

Here is a simpler solution in Bioc devel for generating the matrix "m" (first three lines above):

m <- do.call(rbind, myList)

Also, I will push a change to R devel so that lengths() preserves matrix dimensions, so they do not need to be carried over.

 

 

ADD COMMENT
1
Entering edit mode

A variant is use DataFrame

df = DataFrame(myList)
keep = rowSums(sapply(df, lengths)) >= ncol(df)
as.list(df[keep,, drop=FALSE])

but the short version of jian-liangli's original filtering + rough attempt seems clean enough

lapply(myList, `[`, keepMe, drop=FALSE)
ADD REPLY
0
Entering edit mode

Thank you Martin, both answer is very well done. 

ADD REPLY
1
Entering edit mode

I edited my answer with a simplification possible with S4Vectors 0.11.18.

ADD REPLY
0
Entering edit mode

Dear Michael:

Thanks again your favor to address my issue. However, I must avoid of converting to NA because I have very important minor details that must be taken into consideration for my specific problem, surely length(NA) is way different from length(integer(0)) to do vector sum. I have to use length(integer(0)) in order to efficiently use geometric property of vector list. the form of myList are very much simulated on my specific data set. Is that possible to make your solution more compatible and easier ? Thank you so much

ADD REPLY

Login before adding your answer.

Traffic: 348 users visited in the last hour
Help About
FAQ
Access RSS
API
Stats

Use of this site constitutes acceptance of our User Agreement and Privacy Policy.

Powered by the version 2.3.6